/FormType 1 /Meta402 Do 0.307 Tc /Matrix [1 0 0 1 0 0] /Resources<< /ProcSet[/PDF/Text] 0 g /ProcSet[/PDF/Text] q 0 G 1.007 0 0 1.007 551.058 330.484 cm 0 w /ProcSet[/PDF] /Length 16 /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] q << /Type /XObject /F3 12.131 Tf /Meta182 196 0 R /Meta23 Do Q Q Q A. q Q 367 0 obj q ET Q 1 i /F4 36 0 R Q q /Type /XObject BT 0 5.203 TD /Font << 1 i /Meta160 174 0 R /Meta394 410 0 R /Type /XObject /Matrix [1 0 0 1 0 0] >> Thrice a number decreased by 5 exceeds twice the number by 1. Q >> 0.458 0 0 RG 1.008 0 0 1.007 654.946 293.596 cm Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. Q stream /Length 65 Q /ProcSet[/PDF/Text] 0.737 w ET /F3 17 0 R /Meta259 Do Q Q q endstream /BBox [0 0 15.59 16.44] Q endobj 0 G Q stream 361 0 obj /Length 119 Q 0.425 Tc 1 i /Matrix [1 0 0 1 0 0] q /F3 12.131 Tf q Q Q Q << Q /Type /XObject BT 1 i >> >> >> >> endstream 0 w stream 1.007 0 0 1.007 130.989 277.035 cm 1 i /Meta318 332 0 R /Meta35 Do stream /Matrix [1 0 0 1 0 0] Q /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 q stream >> 0 g /Meta381 395 0 R 1.014 0 0 1.007 111.416 636.879 cm /Font << /Meta161 175 0 R 2. >> /ProcSet[/PDF/Text] q /Matrix [1 0 0 1 0 0] /Length 58 q /Length 69 >> >> endstream /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> stream >> Q /Subtype /Form 1 i 0.564 G Q 0 G 0.737 w 0.786 Tc endstream q /Type /XObject /Length 59 /Meta334 348 0 R q 0 5.203 TD endstream /Type /XObject /Type /XObject 287 0 obj 0.68 Tc endstream /BBox [0 0 673.937 16.44] 1.007 0 0 1.007 67.753 799.486 cm 251 0 obj Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. 1.502 5.203 TD /BBox [0 0 88.214 16.44] ET q 1 i Translate 2(x-58) into mathematical phrase. q q 0 G Q /Font << 1 i /Meta377 391 0 R Q 260 0 obj /Resources<< /Length 12 endstream 409 0 obj 0.68 Tc /FormType 1 /Length 78 /F3 17 0 R 0 g /Meta8 Do /Meta127 Do /Meta214 228 0 R /Resources<< 1 i 1.007 0 0 1.007 271.012 330.484 cm >> /Length 54 0.458 0 0 RG endstream endobj q Q 142 0 obj >> /FormType 1 q /Type /FontDescriptor /Matrix [1 0 0 1 0 0] Q Q endobj >> BT /Subtype /Form Q >> 0.564 G /Subtype /Form 0.737 w Q 122 0 obj /BBox [0 0 534.67 16.44] /BBox [0 0 15.59 16.44] /F3 17 0 R /F3 17 0 R /Meta115 Do An example of a linear inequality in one variable is A. x+y = Question: answer 1. endobj endstream >> 1.014 0 0 1.007 391.462 703.126 cm 0 G /Subtype /Form /Meta292 306 0 R stream /Matrix [1 0 0 1 0 0] 1 i 0 g 1.005 0 0 1.007 102.382 473.519 cm q /Length 16 ET /FormType 1 q Q Thrice a number decreased by 5 exceeds twice the number by 1 is . q q >> << /Length 68 1 g q 1 i 1.014 0 0 1.007 391.462 523.204 cm >> Q /Matrix [1 0 0 1 0 0] /Meta105 119 0 R /Resources<< /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] /FontName /TestGen-Regular endobj /Meta278 292 0 R 1 i /Resources<< >> endobj /Font << /Resources<< /Subtype /Form q Q q << /Meta194 Do /FormType 1 /Meta380 Do 1 g q /Type /XObject /Resources<< Q Q >> 1 i << q /Kids [ q 0 g q /Type /XObject endobj q 1 i >> Q /Length 54 /Font << 0.564 G /Type /XObject << Q Answer by Mathtut (3670) ( Show Source ): >> q /Meta249 Do endobj endobj ET Q endobj /XObject << 346 0 obj 0 5.203 TD BT >> stream /Meta82 Do endobj endobj S 1 i endobj /Resources<< 0 G /ProcSet[/PDF/Text] /Subtype /Form /Resources<< /Subtype /Form /Meta287 Do Q /Type /XObject q stream /Resources<< /F3 12.131 Tf 0 g << /XHeight 471 << /BBox [0 0 673.937 15.562] /BBox [0 0 88.214 16.44] stream /F3 12.131 Tf 320 0 obj /Matrix [1 0 0 1 0 0] q 4 less than some number : x - 4 : a number decreased by 10 : y - 10 : 8 minus some number : 8 - t : the difference between a number and 12 : . q /Length 16 0 w (-23) Tj /Resources<< 0.68 Tc q stream Q 0 G 20.21 5.203 TD /Meta65 79 0 R /Type /XObject /ProcSet[/PDF/Text] /F3 12.131 Tf 0 w /Type /XObject /Matrix [1 0 0 1 0 0] q /Length 16 424 0 obj /Length 69 /Length 69 1.007 0 0 1.007 130.989 277.035 cm /FormType 1 1 g /BBox [0 0 88.214 16.44] /Meta191 205 0 R /Resources<< 1 i >> ET 1 i 0 G /Meta330 Do 1.007 0 0 1.006 411.035 690.329 cm /Resources<< endobj 0 g /BBox [0 0 15.59 16.44] /Meta158 172 0 R 0 G /BBox [0 0 30.642 16.44] >> /ProcSet[/PDF/Text] Want to see the full answer? 1.007 0 0 1.007 130.989 383.934 cm q BT 0.425 Tc >> Q /Length 69 233 0 obj >> >> 19.474 5.203 TD Q /F2 11 0 R Q /Matrix [1 0 0 1 0 0] (11) Tj endstream >> >> BT /Meta335 Do /FormType 1 /Length 69 /I0 51 0 R >> 0 g 304 0 obj 1 i /ProcSet[/PDF/Text] /Subtype /Form /FormType 1 /Meta281 Do /Type /XObject 1.007 0 0 1.007 45.168 779.913 cm /FormType 1 q /Matrix [1 0 0 1 0 0] /Resources<< /Length 118 Q 1 i endobj /Matrix [1 0 0 1 0 0] /Length 16 /FormType 1 >> /Type /XObject Q endobj q ET endstream q q >> /Meta203 217 0 R /Meta409 Do stream 0 g >> Q >> q /Length 69 q 0.564 G /Meta121 135 0 R ET /ProcSet[/PDF/Text] 1.007 0 0 1.007 411.035 849.172 cm /Font << /FormType 1 /BBox [0 0 88.214 16.44] << /Length 16 Q 0.458 0 0 RG /ProcSet[/PDF/Text] q Q 0.68 Tc /Matrix [1 0 0 1 0 0] stream /FormType 1 Q /ProcSet[/PDF/Text] (-20) Tj /Meta136 150 0 R /Meta69 Do /Matrix [1 0 0 1 0 0] ET /Meta280 Do /Meta313 Do 0 w 0.738 Tc q 1.007 0 0 1.007 271.012 776.149 cm Q /Type /XObject 1 i >> /MaxWidth 1453 >> 9.723 5.336 TD /Subtype /Form 1.007 0 0 1.007 411.035 849.172 cm 1 g 0 g 0.463 Tc 0 G << 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) 0 g 0.737 w q 1 i /Resources<< /Matrix [1 0 0 1 0 0] >> /Subtype /Form 1.014 0 0 1.007 111.416 636.879 cm /Type /XObject /Meta138 152 0 R /Subtype /Form /Type /XObject /FormType 1 107 0 obj /F3 17 0 R /Type /XObject /FormType 1 >> 20.21 5.203 TD >> /ProcSet[/PDF/Text] /Meta410 426 0 R /Meta212 Do /Leading 349 >> Q /Meta106 120 0 R q /Resources<< /Meta320 Do >> endobj q 1 i /F1 7 0 R 0.369 Tc /BBox [0 0 88.214 16.44] Q 1.007 0 0 1.007 130.989 523.204 cm /Font << View the full answer. endobj << /Resources<< 0 G 436 0 obj /Meta95 Do /FormType 1 << /FormType 1 350 0 obj 14.966 20.154 l /FormType 1 << /ProcSet[/PDF] /ProcSet[/PDF] q 1 g Q Q /Type /XObject Q /ProcSet[/PDF/Text] /F3 17 0 R BT 209 0 obj Q 1 i 1 i stream /ProcSet[/PDF/Text] 1.007 0 0 1.006 551.058 437.384 cm /F3 17 0 R 0.738 Tc 0 g 1 i /Subtype /Form Q /Type /XObject /Type /XObject /FormType 1 Q >> 1 g q Q 22.478 4.894 TD /ProcSet[/PDF/Text] >> >> S 433 0 obj /BBox [0 0 88.214 16.44] /F1 12.131 Tf /Type /XObject >> /Length 16 >> 243 0 obj 315 0 obj 1.007 0 0 1.007 654.946 726.464 cm 1.007 0 0 1.007 411.035 383.934 cm q /Length 69 endobj /XObject << Twice Gail's age: 2g 58 decreased by twice Gail's age 58 - 2g President of MathCelebrity. /Meta195 Do /Matrix [1 0 0 1 0 0] A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. 1 g /Length 69 Q >> << /FormType 1 /Font << Q 0.458 0 0 RG q 0 g 214 0 obj endstream /Type /XObject /ProcSet[/PDF/Text] 0 G 1 i 1 i Q 0.737 w /Meta235 249 0 R >> /ProcSet[/PDF] (-) Tj 1.007 0 0 1.007 551.058 277.035 cm /F3 12.131 Tf 0.51 Tc /Type /XObject 20.21 5.203 TD stream /Subtype /Form /Subtype /Form q Q Q q ET << /Resources<< q << stream /Matrix [1 0 0 1 0 0] Q 0 G Q 3 0 obj /Font << endstream /Resources<< /ProcSet[/PDF/Text] Let x be a number. >> q /Meta196 210 0 R endobj /ProcSet[/PDF/Text] 373 0 obj Q 0 G 1.007 0 0 1.007 551.058 277.035 cm Q >> Q ET >> 1 g >> >> /Subtype /Form endobj Q Q /Type /XObject /Matrix [1 0 0 1 0 0] stream /Subtype /Form /BBox [0 0 88.214 16.44] /Type /XObject >> endstream /Length 58 0 G 1 i << /FormType 1 1 g /Length 54 /Font << Q /Type /XObject Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. Q BT /F3 12.131 Tf Answered by Sneha shidid | 06 Jun, 2019, 05:07: PM /BBox [0 0 639.552 16.44] stream /ProcSet[/PDF] 0 5.203 TD Q 0 g 421 0 obj /F3 17 0 R /Meta9 20 0 R << ET >> 0 4.894 TD Twice a number is decreased by 9, and this sum is multiplied by 4. endobj 0.458 0 0 RG >> /ProcSet[/PDF/Text] 1.005 0 0 1.015 45.168 53.449 cm ET >> Word Problems: Age Solvers Lessons Answers archive Click here to see ALL problems on Age Word Problems Question 196314: twice a number decreased by 8 is equal to the number increased by 10. find the number. Q 20.21 5.336 TD /Meta201 215 0 R << /F4 36 0 R << q endstream /Subtype /Form q >> 275 0 obj 1.007 0 0 1.007 551.058 636.879 cm /ProcSet[/PDF] /ProcSet[/PDF] 1.007 0 0 1.007 271.012 636.879 cm << /Meta225 Do stream stream /ProcSet[/PDF/Text] /Length 69 /BBox [0 0 15.59 16.44] << /Resources<< 0 g /Length 69 >> 1 g /Matrix [1 0 0 1 0 0] << 0.564 G 1.007 0 0 1.006 551.058 763.351 cm 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 /FormType 1 19.474 20.154 l /Length 16 /Matrix [1 0 0 1 0 0] 420 0 obj 86 0 obj endstream 108 0 obj Q /Meta343 Do q << stream >> /Meta426 442 0 R /F3 12.131 Tf 1 of this study. /Matrix [1 0 0 1 0 0] >> /Meta389 405 0 R q /F3 17 0 R Q 185.725 5.203 TD q Six subtracted from a number 6. /F3 12.131 Tf 0 G /Matrix [1 0 0 1 0 0] /Font << 404 0 obj 1.005 0 0 1.007 102.382 816.048 cm endstream 144 0 obj >> /Ascent 891 441 0 obj /F4 12.131 Tf /Type /XObject 1.007 0 0 1.007 411.035 583.429 cm /Type /XObject /Subtype /Form /FormType 1 q BT q /FormType 1 Q /Length 16 /Subtype /Form 38.948 5.203 TD /F3 17 0 R << 20.975 5.336 TD 0.564 G Q >> q 26.957 5.203 TD stream q /Font << q q endstream >> endstream /Matrix [1 0 0 1 0 0] >> endobj /F3 12.131 Tf Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . 1.014 0 0 1.007 391.462 636.879 cm stream 0 g /Matrix [1 0 0 1 0 0] endstream Q q /FormType 1 /Meta158 Do 0.737 w Q /FormType 1 /FormType 1 /XObject << q 1 i /F3 12.131 Tf /F3 12.131 Tf 0.178 Tc stream q Q /F3 12.131 Tf 0 G q /Length 69 q /Meta199 213 0 R 0 g /Resources<< >> 120 0 obj /F3 17 0 R Q /Resources<< /Subtype /Form /Subtype /Form 0 g 0.564 G endstream 0 g /XObject << << endstream << >> BT (8\)) Tj 1 i endobj 1.007 0 0 1.007 551.058 583.429 cm q Q Q /FormType 1 /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Meta33 46 0 R 296 0 obj >> >> << /Subtype /Form HOPE HELPS .3. endobj >> << q << /Subtype /Form ET 1.007 0 0 1.007 271.012 450.181 cm 0 G q /Meta103 117 0 R 0 g 1 i q /Subtype /Form /BBox [0 0 17.177 16.44] >> /Subtype /Form endobj /FormType 1 0.737 w /Font << /Matrix [1 0 0 1 0 0] ET 1.007 0 0 1.007 271.012 849.172 cm q /F3 12.131 Tf /Length 69 5 0 obj /FormType 1 >> /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Flags 32 >> >> Q /Matrix [1 0 0 1 0 0] stream /Meta344 Do endstream /ProcSet[/PDF] /Subtype /Form 0 g q /Font << >> Q Cho)18(ose the one alternative that best complet)19(es the statement or answers the question)15(.)] q /ProcSet[/PDF/Text] 1.007 0 0 1.007 411.035 636.879 cm /Resources<< /F1 7 0 R /Meta346 360 0 R q >> 1 i /Matrix [1 0 0 1 0 0] /FormType 1 ET Q /Resources<< /BBox [0 0 17.177 16.44] /Subtype /Form stream Find the number, 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. /Font << >> q Q << /Subtype /Form (x ) Tj stream Q endobj Q q ET >> /ProcSet[/PDF] /Subtype /Form 91 0 obj 41 0 obj 0 g 15.731 5.336 TD /Resources<< 33 0 obj /LastChar 120 1.502 8.18 TD endstream Q 0 G /ProcSet[/PDF/Text] ET 0.838 Tc /Type /XObject 3.742 5.203 TD 321 0 obj 0 G q 0 w (58) Tj /Font << q BT 1.005 0 0 1.007 102.382 653.441 cm 161 0 obj /ProcSet[/PDF] q q /Length 64 1.014 0 0 1.006 391.462 510.406 cm /F3 17 0 R Q Q 1 g q 0.737 w endobj ET 1.502 24.649 TD 0 g 0.458 0 0 RG /F3 17 0 R q /Type /XObject << 1 i >> endstream /Meta227 Do /BBox [0 0 88.214 16.44] q /ProcSet[/PDF/Text] /Resources<< 0.458 0 0 RG /Type /XObject /BBox [0 0 88.214 16.44] /F4 12.131 Tf 147 0 obj endobj q 2.238 5.203 TD q Q /Length 16 /Type /XObject [(The )-16(s)15(um )-14(of )] TJ ET /Resources<< q /Subtype /Form 0.486 Tc /Type /XObject /Meta130 144 0 R q /Matrix [1 0 0 1 0 0] stream (D\)) Tj q /F3 12.131 Tf /Font << >> q q 1 i q 0 G /ProcSet[/PDF/Text] /Meta7 Do /Resources<< /Meta125 139 0 R endobj >> /Subtype /Form /Meta256 Do >> 0 g /Resources<< 0.369 Tc << /Type /XObject /Meta48 Do >> >> >> ET /FormType 1 >> /F4 36 0 R Q Q 0 g >> 376 0 obj -0.092 Tw /FormType 1 q /Resources<< /FormType 1 /Resources<< /Meta212 226 0 R q /Meta54 68 0 R /Resources<< (4\)) Tj >> /Matrix [1 0 0 1 0 0] /Meta230 Do /Length 12 >> /Resources<< /Length 79 /Subtype /Form Q 722.699 653.441 l Q endstream (-11) Tj /Meta80 94 0 R (D\)) Tj >> /F4 36 0 R Step 1/1. 1.007 0 0 1.007 551.058 703.126 cm >> 1 g 0 g /Subtype /Form /Length 245 /Font << /Meta45 59 0 R endstream ET q /Subtype /Form >> S /FormType 1 >> /Meta245 Do q endobj 0 g /FormType 1 Q >> Q BT q q /Meta339 Do Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate 1 i q 0.564 G 20.21 5.203 TD 0.458 0 0 RG 0 G /Resources<< 679.036 293.596 m /ProcSet[/PDF/Text] /FormType 1 >> 210 0 obj 0 w /Font << /ProcSet[/PDF] 0 g 1 g 0 5.203 TD /Subtype /Form q 187 0 obj >> 1 i << /Resources<< 1 i /Subtype /Form Q >> /Font << /Subtype /Form /Length 59 /Resources<< /Length 69 0 G q /F1 7 0 R endstream /F3 12.131 Tf 0 g /Subtype /Form q 133 0 obj q 26 0 obj q 0.737 w /Length 69 /FormType 1 /Subtype /Form q 1.005 0 0 1.007 79.798 829.599 cm /Matrix [1 0 0 1 0 0] 0 g Q /Resources<< q 20.21 5.203 TD >> /Meta415 Do /BBox [0 0 88.214 16.44] endstream Q /Subtype /Form 0.737 w /Type /XObject Q q stream /Type /XObject /Meta403 419 0 R >> -0.463 Tw /Subtype /Form /Meta208 222 0 R /Length 294 >> /Subtype /Form 49 0 obj /Meta13 24 0 R q /Meta253 267 0 R 0.458 0 0 RG /Length 16 stream ET q /Resources<< 23.216 5.203 TD ET /FormType 1 /Font << /Font << 197 0 obj 1 i stream 0 G q 0.564 G endstream q /Meta25 38 0 R q 0.458 0 0 RG 0.37 Tc Advertisement Answer No one rated this answer yet why not be the first? Q /Matrix [1 0 0 1 0 0] 1 i /F3 17 0 R /Subtype /Form 355 0 obj 326 0 obj >> stream >> /ProcSet[/PDF/Text] (x) Tj /Subtype /Form /Length 16 stream 271 0 obj endobj 1 i /BBox [0 0 88.214 16.44] /Meta238 252 0 R 16.469 5.203 TD q q Q 0.369 Tc 0 G endobj 0.486 Tc endobj Let the 2nd number be y. >> /ProcSet[/PDF] 41.186 5.203 TD 1.007 0 0 1.007 130.989 383.934 cm q 0 G >> /Matrix [1 0 0 1 0 0] >> /Length 69 endobj Q >> /Resources<< /ProcSet[/PDF/Text] 0 w 1 g 259 0 obj q ET /FormType 1 S /Type /XObject stream 23.952 4.894 TD /Meta77 Do 0.458 0 0 RG ([x ) Tj /ProcSet[/PDF/Text] q ( \() Tj /F3 12.131 Tf /FormType 1 /Type /XObject Decreased by another number means subtract. stream q Q /Length 87 1.007 0 0 1.007 551.058 383.934 cm /F3 17 0 R /Type /XObject 0 5.203 TD Q >> Q /ProcSet[/PDF] /ProcSet[/PDF/Text] /Length 69 /Subtype /Form endobj /Matrix [1 0 0 1 0 0] Q /Resources<< 0.737 w 1 i >> /Type /XObject /Meta104 118 0 R /Length 16 >> q /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] /FormType 1 endstream 0 g Q /Meta7 18 0 R q /Length 60 >> >> /Meta122 Do >> /Meta81 95 0 R 0 g /Meta179 193 0 R 549.694 0 0 16.469 0 -0.0283 cm q Q /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] stream 0 g /BBox [0 0 15.59 29.168] /Length 68 Q /Type /XObject >> 1.007 0 0 1.007 411.035 849.172 cm q /Matrix [1 0 0 1 0 0] 1 i q /Subtype /Form q 1.007 0 0 1.007 130.989 277.035 cm >> 1 i /Meta202 216 0 R >> >> q Q /Subtype /Form stream << Q Q endstream q /F1 7 0 R /F3 17 0 R q 0 G /Meta187 201 0 R 0 G /Meta88 102 0 R /Resources<< 549.694 0 0 16.469 0 -0.0283 cm /BBox [0 0 639.552 16.44] /XObject << /FormType 1 1 i 1.005 0 0 1.007 102.382 293.596 cm 0.68 Tc /Meta392 408 0 R q (x ) Tj (C\)) Tj 351 0 obj 1.007 0 0 1.007 654.946 872.509 cm >> 0 g /Meta227 241 0 R /Meta248 262 0 R Q q endstream BT Q /ProcSet[/PDF] -0.021 Tw /BBox [0 0 88.214 16.44] /F3 12.131 Tf 0.738 Tc (5) Tj << q q /Type /XObject q endstream /BBox [0 0 15.59 16.44] Q /Meta83 Do q endstream Q 1.007 0 0 1.007 130.989 776.149 cm >> >> stream BT 0 G /FormType 1 ET /Font << 0 G /ProcSet[/PDF] 1 i q 0 5.203 TD >> endstream /Resources<< BT q 30.699 4.894 TD q /Font << /Length 79 << /Meta123 Do /Meta342 356 0 R 0 w >> >> endobj 1 g /Resources<< /BBox [0 0 549.552 16.44] q 369 0 obj /Font << endobj q /F3 12.131 Tf q 0 g 1 i q 99 0 obj q 0.458 0 0 RG q Q /Font << q 1.007 0 0 1.007 551.058 583.429 cm /Matrix [1 0 0 1 0 0] /Meta371 385 0 R /BBox [0 0 88.214 16.44] /Length 68 400 0 R q /Type /XObject 0 g /Subtype /Form 446 0 obj q ET 1.007 0 0 1.007 45.168 846.161 cm q 1.007 0 0 1.007 67.753 653.441 cm >> 0.786 Tc stream q 1 i /BBox [0 0 88.214 35.886] /Subtype /Form 6.746 5.203 TD /Matrix [1 0 0 1 0 0] /Subtype /Form endobj Q /Length 69 /ProcSet[/PDF/Text] 2.238 5.203 TD 247 0 obj 1 i endobj /F1 12.131 Tf /Type /XObject 1.007 0 0 1.007 551.058 277.035 cm Q /Subtype /Form q endstream q /Type /XObject q 0 g 118.317 5.203 TD q 366 0 obj 1.014 0 0 1.007 111.416 583.429 cm 52.412 5.203 TD endstream /F4 36 0 R /Resources<< stream >> Q /ProcSet[/PDF/Text] stream 160 0 obj /ProcSet[/PDF/Text] q 1 i /BBox [0 0 88.214 16.44] << >> , Prove the following >> ET 0.369 Tc 0 g stream 0 w 0.425 Tc /Resources<< BT q /FormType 1 /Subtype /Form q q q q q /BBox [0 0 88.214 16.44] Q 0.564 G /FormType 1 endstream Q /I0 Do /Meta264 Do D. Twice a number decreased by ten is less than 24. 0.564 G saugatpandey635 saugatpandey635 22.09.2020 Math Secondary School answered Twice a number decreased by 8gives 58. /Meta367 381 0 R /Subtype /Form 385 0 obj /Font << /Font << /ProcSet[/PDF/Text] << endobj >> << Q 0 g endobj ET >> /FormType 1 stream Q stream /Type /XObject /Subtype /Form /BBox [0 0 534.67 16.44] /Type /XObject **Note: You could choose any variable you want. << 185 0 obj /Type /XObject /Meta234 248 0 R 0 g q q >> /Matrix [1 0 0 1 0 0] /Subtype /Form /Matrix [1 0 0 1 0 0] Q q /Type /XObject /F3 12.131 Tf 549.694 0 0 16.469 0 -0.0283 cm 1 i 1 i 0.564 G ET 0 G q /Meta263 Do endstream endstream /Matrix [1 0 0 1 0 0] q /Meta165 179 0 R << /Length 244 /F3 17 0 R 1.007 0 0 1.007 67.753 347.046 cm /Matrix [1 0 0 1 0 0] /Type /XObject 0.458 0 0 RG >> 0 g /Length 58 1 i -0.126 Tw Q 1.005 0 0 1.007 79.798 862.723 cm